On a 120 km long railway track ,a train travel s the first 30km at a uniform speed of 30km/h. calculate the speed with which the train should move rest of the track so as to get the average speed of 60km/h for the entire trip.
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Hi...
Given that,
Total distance covered, S = 120 km
First 30 km is covered at 30 km/h.
Time taken is, t 1 = 30/30 = 1 hour
Let the train covers next 90 km at speed x km/h.
Then the time taken is, t 2 = 90/x hour
Average speed = total distance/total time
=> 60 = 120/(t 1 + t 2 )
=> 60 = 120/(1 + 90/x)
=> 1 + 90/x = 2
=> 90/x = 1
=> x = 90 km/h
Thus, to achieve an average speed of 60 km/h the train must travel the next 90 km at 90 km/h. .
Hope this helps u!!
Given that,
Total distance covered, S = 120 km
First 30 km is covered at 30 km/h.
Time taken is, t 1 = 30/30 = 1 hour
Let the train covers next 90 km at speed x km/h.
Then the time taken is, t 2 = 90/x hour
Average speed = total distance/total time
=> 60 = 120/(t 1 + t 2 )
=> 60 = 120/(1 + 90/x)
=> 1 + 90/x = 2
=> 90/x = 1
=> x = 90 km/h
Thus, to achieve an average speed of 60 km/h the train must travel the next 90 km at 90 km/h. .
Hope this helps u!!
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