On a 120 km track a train travels the first 30 km at a uniform speed of 30 km/h. Calculate the speed with train should move rest of the track so as to get the average speed of 60 km/h for the entire trip.
Answers
Answered by
16
Given that,
Total distance covered, S = 120 km
First 30 km is covered at 30 km/h.
Time taken is, t1 = 30/30 = 1 hour
Let the train covers next 90 km at speed x km/h.
Then the time taken is, t2 = 90/x hour
Average speed = total distance/total time
=> 60 = 120/(t1+t2)
60 = 120/(1 + 90/x)
1 + 90/x = 2
90/x = 1
=> x = 90 km/h
Thus, to achieve an average speed of 60 km/h the train must travel the next 90 km at 90 km/
Total distance covered, S = 120 km
First 30 km is covered at 30 km/h.
Time taken is, t1 = 30/30 = 1 hour
Let the train covers next 90 km at speed x km/h.
Then the time taken is, t2 = 90/x hour
Average speed = total distance/total time
=> 60 = 120/(t1+t2)
60 = 120/(1 + 90/x)
1 + 90/x = 2
90/x = 1
=> x = 90 km/h
Thus, to achieve an average speed of 60 km/h the train must travel the next 90 km at 90 km/
sabrinfatimah:
Thanks a lot
Answered by
5
if the train travelled 30km/hour to complete 30 km so its speed should be 90km/hour to complete 90km.
Similar questions