Question

on a 120 km track a train travels the first 30 km at a uniform speed of 30 km/h how fast much the train travel the next 90 km sa as to average 60 km/h for the entire trip​

Answer 1

Answer:

$\sf\green{\underline{\boxed{Average \: speed= \frac{Total \: distance}{Total \: time \: taken}}}}$

$v= \frac{d}{t}$

For 120 km,

$\leadsto$$t = \frac{120 \: km}{60 \: km/h}$= 2 hr ____(1)

For 1st 30 km,

$\leadsto$$t(1) = \frac{30 \: km}{30 \: km \: h} = 1hr$

For remaining 90 km,

$t(2) =t - t(1) = 2 - 1 = 1 \: hr$

$speed =\frac{distance}{time} \: \: \: or \: \: \: v(2) = \frac{d(2)}{t(2)} \\= \: \sf\blue{\boxed{\frac{90}{1} = 90 \: km/ h}}$

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