Physics, asked by Arohi28876, 1 year ago

On a 120km track, a train travels the first 30 km at a uniform speed of 30 km/hr.
How fast must the train travel the next 90km so as to average 60km/hr for the entire trip..?
Explanation required​

Answers

Answered by xandacross12
1

Answer:

90kmph

Explanation:

taking speed s1=30kmph

we have to calc. s2

also we have to calc. average that means {(s1 + s2)/2} =60kmph(given)

now calc. s2 .

let me know if it was helpful


xandacross12: sorry it'll be solved as 60=(d1+d2)/(t1+t2). where t1= 1 since uniform speed per hour and let t2 =x then solve it to get the ans. here x=1. ....then calc. s2 =d2/t2
xandacross12: the answer remains same as per the frst cmmnt bt it is the very formulae to be used not that one because it is not told that both the speeds are uniform
Answered by Avinash3474
1

Explanation:

take speed =s1=30 kmph

calculate s2

we have to calculate.average that means {(s1+s2)/2} = 60 kmph(given)

now calculate s2.

Or

Take

60=(d1+d2)/(t1+t2)

This will also help you

where t1=1

And let t2=x

Then calculated it

s2=d2/t2


Avinash3474: hi
Avinash3474: friend
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