On a 120km track, a train travels the first 30 km at a uniform speed of 30 km/hr.
How fast must the train travel the next 90km so as to average 60km/hr for the entire trip..?
Explanation required
Answers
Answered by
1
Answer:
90kmph
Explanation:
taking speed s1=30kmph
we have to calc. s2
also we have to calc. average that means {(s1 + s2)/2} =60kmph(given)
now calc. s2 .
let me know if it was helpful
xandacross12:
sorry it'll be solved as 60=(d1+d2)/(t1+t2). where t1= 1 since uniform speed per hour and let t2 =x then solve it to get the ans. here x=1. ....then calc. s2 =d2/t2
Answered by
1
Explanation:
take speed =s1=30 kmph
calculate s2
we have to calculate.average that means {(s1+s2)/2} = 60 kmph(given)
now calculate s2.
Or
Take
60=(d1+d2)/(t1+t2)
This will also help you
where t1=1
And let t2=x
Then calculated it
s2=d2/t2
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