Physics, asked by ludirm1821, 1 year ago

On a 120km track, a train travels the first 30 km at a uniform speed of 30km/hr. How fast must the train travel the next 90 km so as to have 90 km/h as average speed






km/hr for the entire trip?

Answers

Answered by snehatheerthamkara
0

Total distance travelled =120 km


Time taken by the train to cover 30km = 30km / 30km/hr

ie, t1= 1 hr


Average speed = total distance / total time

90km/hr = 120 /1+x

1+x = 120/90

x = 4/3 -1

x = 1/3

V2 = 90÷ 1/3

= 270km/hr

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