On a 120km track,a train travels the first 30 km at uniform speed of 36 km/h how fast must the train travel the next 90km so as to average speed 60km/h for the entire trip?
khushiarora2220:
Plz reply fast......
Anyone??????
I've replied khushi
Answers
Answered by
2
First 30 km travelled at speed of 36 km/h
Therefore time taken=Distance/Speed
=30/36=5/6 hours
For averaging 60 km/h total time to be taken=120/60=2hours
Therefore time left=2-5/6
=12-5=7/6 hours
Now, remaining distance=90 km
Therefore speed at which train has to travel=90/(7/6)=90×6/7=540/7=77.14 km/h
Plz mark as brainliest :D
Therefore time taken=Distance/Speed
=30/36=5/6 hours
For averaging 60 km/h total time to be taken=120/60=2hours
Therefore time left=2-5/6
=12-5=7/6 hours
Now, remaining distance=90 km
Therefore speed at which train has to travel=90/(7/6)=90×6/7=540/7=77.14 km/h
Plz mark as brainliest :D
Okk
Similar questions