On a 150 km track, a train travels the first 50 km at a uniform speed of 20 km/h. How fast the train must travel next 100 km so as to maintain the average speed of 40 km/h for the whole journey?
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Answered by
1
[(50*20)+(100*x)]/150=40
then x=(40*150-1000)/100
x=50 kmph
then x=(40*150-1000)/100
x=50 kmph
Answered by
1
time =200/60=20/6
average speed=Total distance/Total time
Time taken 50km=5/4
remaining time=20/6-5/4=25/12
speed=distance/time
150*12/25=72
remaining speed=72km/h
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