on a 300 km track A train travels the first 30 km at a uniform speed of 60 km per hour how fast must the train travel the next 270 km so as the average speed 90 km per hour for entire trip
Answers
Answered by
2
Answer:
average speed=distance travelled/time taken
90=300/time taken
time taken = 300/90
time taken = 3.3hr
1st train= time=30/60
=0.5 hr
2nd train= let speed be x
d=270 km
speed=distance/time
x=270/time
time=270/x
adding
0.5 + 270/x = 3.3
270/x = 3.3-0.5
270/x = 2.8
x = 2.8×270
x = 756km/h
himanshu3965:
bro it is right or not?
Answered by
2
Answer:95.29
Explanation:
In the following question assume the time for going the rest 270km be x.Now through the avg speed formula calculate the value of x and then find the speed using 270/x
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