Question

on a 3kg mass,5Nof force acts for 0.1 sec .The impulse imparted to the mass is (in kg m/s)​

Answer 1

Answer:

The impulse imparted to the mass is 0.5 kg-m/s.

Step-by-step explanation:

It is given that,

Mass of the object, m = 3 kg

Force acting on the object, F = 5 N

Time of contact, t = 0.1 s

Let J is the impulse imparted to mass. It is equal to the product of force and time of contact. It is given by :

J = F * t

J = 5 N *  0.1s

J = 0.5 kg-m/s

So, the impulse imparted to the mass is 0.5 kg-m/s. Hence, this is the required solution.

Answer 2

Answer:

I also want to know the answer

thank you for asking this question dear