On a 60 km stretch of road a cyclist travels first 20 km at a uniform speed of 20km/hr. How fast he must travel the remaining distance so that his average speed is 10 km/hr for the entire trip.
Answer is given 8 km/hr, but i want the complete solution of this question.
Answers
Answered by
7
Answer:
8hr
Explanation:
Given
Total distance=60km
Average speed=10km/hr
Uniform speed to travel 20km=20km/hr
Time taken to travel 20 km =
20km/(20km/hr)
=1hr
So,
Let the time taken for rest distance that is (60-20=40)km be x
We know,
Average speed=
Total distance /Total time
60/x+1=10
10x+10=50
x=5
Time to travel 40km=5hr
Speed =40km/5hr
=8km/hr
Answered by
2
Given
Total distance=60km
Average speed=10km/hr
Uniform speed to travel 20km=20km/hr
Time taken to travel 20 km =
20km/(20km/hr)
=1hr
So,
Let the time taken for rest distance that is (60-20=40)km be x
We know,
Average speed=
Total distance /Total time
60/x+1=10
10x+10=50
x=5
Time to travel 40km=5hr
Speed =40km/5hr
=8km/hr
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