On a 60km State road up bus travel the first 30 kilometre with a uniform speed of 30 km h -1 how fast must the bus travel the next 30 km so as to have average speed of 40 km h -1 for the entry trip
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Given:
- Total distance = 60 km
- Speed of bus of first 30km = 30 km/h
To find:
- Speed of bus of second 30km where the average speed becomes 40km/h
Solution:
Average speed = 40km/h
Using the formula
Average speed = 2V1V2/V1 + V2
Substituting
- V1 = 30 km/h
- V2 = ?
→ 40 = 2(30)(V2)/30 + V2
→ 40/1 = 60V2/30 + V2
By Cross-multiplyng
→ 60V2 = 40(30 + V2)
→ 60V2 = 1200 + 40V2
→ 60V2 - 40V2 = 1200
→ 20V2 = 1200
→ V2 = 1200/20
→ V2 = 60 km/h
Hence , the speed in second 30km where it's average speed becomes 40km/h = 60km/h.
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