on a 60km straight road, a bus travels the first 30km with a uniform speed of 30kmh-1. how fast much the bus travel the next 30km so as to have average speed of 40kmh'1 for the entire trip
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Average speed = Total distance / Time taken
40=60/t
t=6/4hour
___________
Now taking values of time separately
t1=30/30
t1=1hour
_
t2=30/x
_____________
6/4=1+30/x
6/4=x+30/x
6x/4=x+30
3x/2=x+30
3x=2x+60
3x-2x=60
x=60
Speed for next 30 km = 60km/h
40=60/t
t=6/4hour
___________
Now taking values of time separately
t1=30/30
t1=1hour
_
t2=30/x
_____________
6/4=1+30/x
6/4=x+30/x
6x/4=x+30
3x/2=x+30
3x=2x+60
3x-2x=60
x=60
Speed for next 30 km = 60km/h
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