on a body of mass 5 kg a force f equals to 2 x N act due to which there is a displacement of x = 0 to x=4m calculate the work done
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Work done is equal to
F × ∆x
= 2 × 4
= 8 J
F × ∆x
= 2 × 4
= 8 J
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Work = force * displacement.
Hence, work done here is
: 2 * 4 = 8 nm
Here, if N is the normal force.. Then, force = 2*5*10= 100Newton
Work = 400nm.
Please mention the force clearly. Is N in 2*N the normal force the ground has on the object?
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