On a bright Sunday morning three friends A, B and C decided to go for fishing and
boating. They decided to leave for the place together in the evening. The journey
was smooth, it just went as scheduled then they reached to the river, and started to set the boat on sail. They were enjoying their ride with full speed. They started
boating from a place to another place which is at a distance of 42 km and then
again returns to the starting place. They took 20 hours in all. The time taken by
them riding 14km downstream is equal to the time taken by them riding 6 km
upstream.
Plz Solve all MCQs
Answers
Given : boating from a place to another place which is at a distance of 42 km and then again returns to the starting place. They took 20 hours in all. The time taken by them riding 14km downstream is equal to the time taken by them riding 6 km upstream
To Find : Boat speed in still water
River speed
Upstream speed
If speed of boat in still water increased by 1 and river speed decreased by 1 then time for return journey
Solution:
D = 42 km
Speed in still water = B km/hr
Speed of stream / river = S km/hr
Upstream speed = B - S km/hr
Down stream speed = B + S km/hr
They took 20 hours in all
=> 42/(B - S) + 42/(B + S) = 20
=> 42( 2B ) = 20 ( B + S)(B - S)
=> 21B = 5 ( B + S)(B - S)
The time taken by
them riding 14km downstream is equal to the time taken by them riding 6 km
=> 14/ (B + S) = 6/(B - S)
=> 7/ (B + S) = 3/(B - S)
=> 7B - 7S = 3B + 3S
=> 4B = 10S
=> 2B = 5S
=> B = 5S/2
or S = 2B/5
21B = 5 ( B + S)(B - S)
=> 21B = 5 ( B + 2B/5)(B - 2B/5)
=> 21B = 5 ( 7B/5)(3B/5)
=> B = 5
S = 2
Boat speed in still water = 5 km/hr
Speed of the river = 2 km/hr
Upstream speed = 5 - 2 = 3 km/hr
Downstream speed = 5 + 2 = 7 km/hr
Boat speed in still water = 5 + 1 = 6 km/hr
Speed of river = 2 - 1 = 1 km/hr
Upstream speed = 6 - 1 = 5 km/hr
Downstream speed = 6 + 1 = 7 km/hr
Time = 42/5 + 42/7
= 8 hrs 24 mins + 6 hrs
= 14 hrs 24 mins
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