Question

On
a
cartesian
plane, the diagonal
of a square lies on
the x-axis. Which of
the following is the
equation of one of
its sides?​

Answer 1

Step-by-step explanation:

Diagonal of the square is along x−2y=0 (1)

The point (3,0) does not lie on (1)

Let the side through this vertex be y−0=m(x−3) (2)

Angle between side (2) and diagonal (1) is 45

0

⇒ 1+m( 21 )m− 21

=tan45

0

⇒

2+m

2m−1

=±1⇒m=3,−

3

1

∴ From (2), the required sides are y−3x+9=0 and 3y+x−3=0