On a certain amount of money at a certain rate of interest simple interest of 2 years is rupees 7500 and if the interest is compounded annually the compound interest of the first 2 years is rupees 7781.25.find the rate of interest and the sum of money.
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The rate of interest and the sum of money are 7.5% and Rs 50000 respectively.
Let Principal money (P) be Rs x.
Time period (T) = 2 years.
Rate (R) = r% p.a.
We know,
Compound Interest (CI) = P[(1 + R)ⁿ - 1]
Here n = 2 years
So,
7781.25 = P [(1 + R)² - 1]
⇒ P [(1 + R)² - 1] = 7781.25 ...(1)
Again, Simple Interest (SI) = PRT
So, 7500 = 2PR
⇒ 2PR = 7500 ...(2)
Dividing (1) by (2),
P [(1 + R)² - 1]/2PR = 7781.25/7500
⇒ [(1 + R)² - 1]/2R = 1.0375
⇒ [(1 + R)² - 1]/R = 2.075
⇒ 1 + R² + 2R - 1 - 2.075R = 0
⇒ R² + 2R - 2.075R = 0
⇒ R² - 0.075R = 0
⇒ R(R-0.075) = 0
From zero product rule,
R = 0.075 or 7.5%
As, 7500 = P*0.075*2
⇒ 0.15P = 7500
⇒ P = 7500/0.15 = 50000
Principal money is Rs 50000
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