Question

On a certain hill station, pure water is found to boil at 95°C.How many grams of NaCl must be added to 2kg water so that it boils at 100°C? (Kb for water =0.52Kkgmol-1, MM of NaCl =58.5 gmol-1)​

Answer 1

Answer:

562.42 g

Explanation:

ΔTb=100−95=5∘,ΔTb=iKbm or m=ΔTbiKb=52×0.52=4.807

1000 g should contain NaCl = 4.807 moles =4.807×58.5g

∴ 2000 g should contain NaCl =2×4.807×58.7=562.42g.