Question

On a certain project, an employer lacked six days of working twice as many days as did his employee. If the sum of the days they worked is 42, how many days did each work? (I need a formula with it, not only the answer) ​

Answer 1

42÷6 will be 7

so seven will be the answer

Answer 2

Employer = 26days

Employee = 16 days

Step-by-step explanation:

Let the employer's working days be 2x-6

Let the employee's working days be x

First, we need to find the value of x

$2x - 6 + x = 42$

$2x + x - 6 = 42$

$3x - 6 = 42$

$3x = 42 + 6$

$3x = 48$

$x = \frac{48}{3}$

$x = 16$

Now, we need to find the no. of days worked by the employer and the employee

$Employer = 2x-6 days$

=$2 \times 16 - 6\: days$

=$32 - 6\:days$

=$26 \: days$

$Employee = x$

=$16 \: days$

Therefore,

• Therefore, Employer = 26 days
• Employee = 16 days