Question

on a certain railway the first and second class fares are 7 paise pe km and 3 paise per km respectively. a man who travelled 100 km spent ₹3.40 in going part of distance by first class and then in second class. how many kilometres did he traveled in first clas?​

Answer 1

AnswEr :

• 1st Class Fare = 7 paise per km
• 2nd Class Fare = 3 paise per km
• He travelled 100 km and spent on the journey Rs. 3.40 on both classes.
• Find km travelled in 1st Class?

First of all we will change all Amount in Paise, so that it will be easy to calculate.

↦ Amount = Rs. 3.40

↦ Amount = Rs. 3 + 40 Paise

• Rs. 1 = 100 Paise

↦ Amount = (3 × 100) Paise + 40 Paise

↦ Amount = 300 Paise + 40 Paise

↦ Amount = 340 Paise

Let the Distance Travelled in 1st Class be n km and, Distance Travelled in 2nd Class be (100 - n) km

• According to the Question Now :

⇒ Amount on (1st + 2nd)Class = 340 Paise

⇒ Dist.₁ × Rate₁ + Dist.₂ × Rate₂ = 340 Paise

⇒ (n × 7) + ((100 - n) × 3) = 340

⇒ 7n + 300 - 3n = 340

⇒ 4n = 340 - 300

⇒ 4n = 40

⇒ n = 40 /4

⇒ n = 10 km

∴ Therefore he travelled 10 km in 1st Class.

Answer 2

Question :----- we have to Find how many kilometres did he traveled in first class ????

Given :-------

• Fair of First class = 7 paise / km
• Fair of second class = 3 paise /km
• Total Distance Man cover = 100km
• Total Money he spent = ₹3.40

Required values in solution :-----

• ₹ 1 = 100 paise ,

than ₹3.40 = 3.40 × 100 = 340 paise

• Let he Travel in First class For = x km

Than he travel in second class = (100-x) km

Solution :--------

it is given that for 1 km First class Fair is = 7 paise

so, For x km Total fair will be = 7x paise

it is also given that for 1 km Second class fair is = 3 paise

so, for (100-x) km Total fair will be = 3(100-x) Paise .

Therefore ,

$7x + 3(100 - x) = 340 \\ \\ 7x + 300 - 3x = 340 \\ \\ 4x = 340 - 300 \\ \\ 4x = 40 \\ \\ x = \frac{ \cancel40}{\cancel4} \\ \\ x \: = 10 \: km$

So , Man Travel 10km in First class and 90 km in second class .....

(Hope it helps you)