Math, asked by naeemabbas511, 2 months ago

On a certain Saturday, Stall A sold 208 burgers and Stall B sold 3 times as many burgers as Stall A.
Stall C sold 85 fewer burgers than Stall B.
How many burgers did Stall C sell?

Answers

Answered by akshatsingh200806
0

Step-by-step explanation:

Number of Burgers Stall A sold = 208 Burgers

Number of burgers Stall B sold = 3 times of Stall A

= 3 × 208

= 624 Burgers

Number of Burgers Stall C sold = 85 less than Stall B (624)

= 624 - 85

= 539 Burgers

Therefore, Number of Burgers Stall C sold is 539.

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