Question

on a certain sum the CI in 2 years amounts to rupees 2256 if the rates for successive years are 8% and 10% respectively find the sum​ . Please solve the question with a proper working

Answer 1

Gɪᴠᴇɴ :-

• Amount = Rs.2256 .
• Time = 2 Years.
• Rate in First Year = 8% .
• Rate in second Year = 10% .

Tᴏ Fɪɴᴅ :-

• Principal ?

Fᴏʀᴍᴜʟᴀ ᴜsᴇᴅ :-

• Amount = Principal * (100 + R1%/100) * (100 + R2%/100)

Sᴏʟᴜᴛɪᴏɴ :-

Let us Assume That the sum was Rs.P.

Putting all values in Above told formula now, we get :-

→ P * (100 + 8/100) * (100 + 10/100) = 2256

→ P * (108/100) * (110/100) = 2256

→ P * (27/25) * (11/10) * 2256

→ P * 27 * 11 = 2256 * 250

→ P = (2256 * 250)/(27*11)

→ P = Rs.1898.98 (Ans.)

Hence, The Required Sum is Rs.1898.98.

Answer 2

${\huge{\bf{\red{\underline{Solution:}}}}}$

${\bf{\blue{\underline{Given:}}}}$

• Amount= 2256
• n= 2 years
• Rate1 = 8%
• Rate2 = 10%

${\bf{\blue{\underline{Find:}}}}$

• Principal =?

${\bf{\blue{\underline{Now:}}}}$

${\implies{\sf{ \: A = P \bigg(1 + \frac{ R_{1} }{100} \bigg) \bigg(1 + \frac{ R_{1}}{100} \bigg)}}}$

${\implies{\sf{ \: A = P\bigg(1 + \frac{ 8}{100} \bigg) \bigg(1 + \frac{ 10}{100} \bigg)}}}$

${\implies{\sf{ \: A = P \bigg( \frac{ 100 + 8}{100} \bigg) \bigg( \frac{ 100 + 10}{100} \bigg)}}}$

${\implies{\sf{ \: A = P \bigg( \frac{ 108}{100} \bigg) \bigg( \frac{ 110}{100} \bigg)}}}$

${\implies{\sf{ \: A= P \bigg( \frac{ 27}{25} \bigg) \bigg( \frac{ 11}{10} \bigg)}}}$

${\implies{\sf{ \: A = P \bigg( \frac{ 297}{250} \bigg) }}}$

${\implies{\sf{ \: 2256 \times 250= P \times 297 }}}$

${\implies{\sf{ \: 564000= p \times 297 }}}$

${\implies{\sf{ \: \frac{564000}{297} = p }}}$

${\implies \boxed{\sf{ \: P = 1898.98rs }}}$