Math, asked by adi1568, 1 year ago

On a circular track of length 1080 m, Srikant is walking at a speed of 90 m/min, Venkat at 72 m/min, and Bala at 60 m/min. If all of them start walking at 5:30 a.m. in the same direction from same starting point, then at what time will they all meet each other at the starting point?

Answers

Answered by Anonymous
5
may be this is your answer
Attachments:

adi1568: galat h
adi1568: ekdum galat h
adi1568: ruko
adi1568: first we have to divide time taken by every person by 1080
adi1568: and then we have to take out the lcm of the numbers that we got after division
adi1568: answer will be 180mins
adi1568: samazh gaye?
manasvikakuste: wrong answer
Answered by RenatoMattice
11

Answer: After 5:30 a.m. , they will meet each other at the starting point at 8:30 p.m.

Step-by-step explanation:

Since we have given that

Length of circular track = 1080  m

Speed of Srikant = 90 m/min

Speed of Venkat = 72 m/min

Speed of Bala = 60 m/min

So, Time taken by Srikant to cover the track is given by \frac{1080}{90}=12\ min

Time taken by Venkat to cover the track is given by \frac{1080}{72}=15\ min

Time taken by Bala to cover the track is given by \frac{1080}{60}=18\ min

so, L.C.M. of 12 min, 15 min, 18 min = 180 min = 3 hours

Hence, after 5:30 a.m. , they will meet each other at the starting point at 8:30 p.m.

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