Math, asked by Senbugha, 8 months ago

On a coordinate grid, the location of a bank is (–4, 8) and the location of a post office is (2, 0). The scale used is 1 unit = 50 m. What is the shortest possible distance between the bank and the post office *​

Answers

Answered by pulakmath007
30

\displaystyle\huge\red{\underline{\underline{Solution}}}

FORMULA TO BE IMPLEMENTED

 \sf{The \:  Distance \:  between \:  two \:  points \: (x_1,y_1) and (x_2,y_2)   \: is\: }

 =  \sf{ \sqrt{{(x_2-x_1)}^{2} +{(y_2-y_1)}^{2}} } \:  \:  \: unit

GIVEN

On a coordinate grid, the location of a bank is (–4, 8) and the location of a post office is (2, 0)

The scale used is 1 unit = 50 m

TO DETERMINE

The shortest possible distance between the bank and the post office

CALCULATION

Let us first plot the points in paper in coordinate system ( Refer to the attachment )

Let the position of bank is A ( - 4, 8 ) & the position of post office is B ( 2, 0 )

From the figure it is clear that the shortest distance between bank & post office is

 \sf{AB \:  =  \sqrt{ {( - 4 - 2)}^{2} +  {(8 - 0)}^{2}  } } \:  \:  \:  \: unit

  \implies\sf{AB \:  =     \sqrt{36 + 64}  } \:  \:  \: unit

  \implies\sf{AB \:  =    10}\:  \:  \: unit

Now The scale used is 1 unit = 50 m

Hence the shortest distance between bank & post office

 =  \sf{(10 \times 50) \:  \: metre}

 =  \sf{500 \:  \: metre}

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Answered by Anonymous
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