Question

On a coordinate plane, a curved line with minimum values of (negative 1.5, negative 2) and (1.5, 2), and a maximum value of (0, 4), crosses the x-axis at (negative 2, 0), (negative 1, 0), (1, 0), and (2, 0), and crosses the y-axis at (0, 4).
Which is an x-intercept of the graphed function?

Answer 1

Answer:

2,4]

Step-by-step explanation:

On a coordinate plane, a curved line has minimum values of (negative 1.56, negative 6) and (3, 0). This means

1) when x=-1.56x=−1.56 , the minimum value of the function is y_{min}=-6y

min

=−6

2) when x=3,x=3, the minimum value of the function is y_{min}=0y

min

=0

Hence, the graphed function has a local minimum of 0, when x=3.x=3.

Therefore, the interval which contains this value of x is [2,4][2,4] because x=3\in [2,4].x=3∈[2,4].