Math, asked by rajpalnamberdar1413, 10 months ago

On a coordinate plane, a line is drawn from point A to point B. Point A is at (negative 8, negative 13) and point B is at (4, 11). What are the x- and y- coordinates of point P on the directed line segment from A to B such that P is One-third the length of the line segment from A to B? x = (StartFraction m Over m + n EndFraction) (x 2 minus x 1) + x 1 y = (StartFraction m Over m + n EndFraction) (y 2 minus y 1) + y 1 (1, 5) (0, 3) (–4, –5) (–5, –7)

Answers

Answered by amitnrw
4

Given : On a coordinate plane, a line is drawn from point A to point B . A (-8 , -13) , B ( 4 , 11) . P on the directed line segment from A to B such that P is One-third the length of the line segment from A to B

To find : Coordinate of P

Solution:

A (-8 , -13)

B ( 4 , 11)

coordinates of point P  ( x , y)

AP  = AB/3

BP = AB - AP = AB - AB/3 = 2AB/3

=> AP : BP = 1 : 2

point P divides line segment AB into 1 : 2 ratio

x =  ( 1 * 4 + 2*(-8))/(1 + 2)   =  -12/3  = -4

y = ( 1 * 11 + 2*(-13))/(1 + 2)  = -15/3 = -5

P = (-4 , - 5)

(-4 , - 5)  is the correct option

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