Question

on a distant planet a body, starting from rest Falls freely for 1. 5s. calculate the distance travelled by the body assuming it to be possessing a uniform acceleration of 20 ms-2

Answer 1

hope u understand the calculations yourself

Answer 2

Given :-

• Initial Velocity = 0 m/s
• Time taken = 1.5 seconds
• Acceleration = 20 m/s²

To Find :-

• Distance travelled by the body = ?

Answer :-

• Distance travelled by the body = 22.5 m

Explaination :-

By using second equation of motion we get :

• s = ut + ½ at²

Where,

• s = Distance travelled
• u = Initial Velocity
• a = Acceleration
• t = Time taken

Now, substituting the given in above equation we get :

→ s = 0 × 1.5 + ½ × 20 × (1.5)²

→ s = ½ × 20 × 2.25

→ s = 10 × 2.25

→ s = 22.5 m

Therefore, distance travelled by the body is 22.5 m.

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Some other Formulas :

• v² = u² + 2as

• v = u + at

• s = ut + ½ at²