Question

On a distant planet body while falling freely gains speed stadiny at the rate of 20m/s during each second of motion.Calculate its acceleration.​

Answer 1

Answer:

AC=0+

2

1

g(t

1

+1)

2

and AB=

2

1

gt

1

2

AC−AB=30m

⟹

2

1

g[(t

1

+1)

2

−t

1

2

]=30

⟹2t

1

+1=

g

60

⟹t

1

=2.56[g=9.8]

AB=

2

1

g(t

1

)

2

=32.1m

Answer 2

GiveN :

• Initial velocity (u) = 0 m/s
• Final velocity (v) = 20 m/s
• Time interval (t) = 1s

To FinD :

• Acceleration of the particle

SolutioN :

Use 1st equation of Kinematics:

⇒ v = u + at

⇒ 20 = 0 + a*1

⇒ 20 = a

Therefore, Acceleration is 20 m/s²