Question

On a field duty some army person have extracted at tent in the shape of a cylinder surmounted by a conical top if the height and diameter of the cylinder part are 2.1cm and 4m the slant height of the clonical part is 2.8m find the area of canvas used by them for making the tent

Answer 1

For the conical part:

r = $\sf{\frac{4m}{2}=2m}$

$\sf{slant\:height=2.8m}$

For the cylindrical part:

r = 2m

h = 2.1m

CSA or the whole tent = CSA of cylindrical part + CSA of a conical part.

$\longrightarrow$$\sf{2\pi \: rh + \pi \: rl = \pi \: r(2h + l)}$

$\longrightarrow$$\sf{ \frac{22}{7} \times 2(2 \times 2.1 + 2.8) {m}^{2}}$

$\longrightarrow$$\sf{\frac{22}{7} \times 2(4.2 + 2.8) {m}^{2}}$

$\longrightarrow$$\sf{\frac{22}{7} \times 2 \times 7 {m}^{2}}$

$\longrightarrow$${\boxed{\sf{\red{{44m}}}}^{2}}$

Cost of canvas required for making the tent

$\longrightarrow$ Rs. 44 × 500

$\longrightarrow$ Rs. 22000