Question

on a figure abc is an equilateral triangle and angle adc =75° find acd​

Answer 1

Answer:

Step-by-step explanation:

Given ABCD is a square and CDE is a equilateral triangle. we have to find the angles ∠AED, ∠EAB and reflex angle of ∠AEC.

Given ABCD square ∴all sides are equal and all angles are of 90°

AB=BC=CD=DA

and also CDE is an equilateral triangle ∴ CD=DE=EC and all angles are of 60°

Now, In ΔADE, ∵AD=AE ⇒ ∠DAE=∠AED

∠ADE=∠ADC-∠EDC=90°-60°=30°

By angle sum property of triangle

∠ADE+∠DAE+∠AED=180°

⇒ 30°+2∠AED=180°

⇒ 2∠AED=150° ⇒ ∠AED=75°

∠EAB=∠DAB-∠DAE=90°-75°=15°

Reflex angle ∠AEC=360°-∠AED-∠DEC=360°-75°-60°=225°