Physics, asked by arpitgupta86566, 8 months ago

On a football ground, a rabbit is at the origin of coordinate system and a dog at the position
(46 m, 28m). The
rabbit runs on the ground with a constant velocity
(7.5i + 10j m / s. ) The dog can run with a speed of 5 m/s. If the dog starts to run immediately the rabbit starts, the minimum time in which the dog could catch the rabbit.​

Answers

Answered by tiwariakdi
0

The correct question may be like:

On a football field, a rabbit is at the starting point and a dog is at a distance of 46 meters horizontally and 28 meters vertically from the rabbit. The rabbit runs with a constant speed of 7.5 meters per second horizontally and 10 meters per second vertically. The dog can run with a speed of 5 meters per second. If the dog starts running as soon as the rabbit starts, what is the shortest time in which the dog can catch the rabbit?

"The shortest time in which the dog can catch the rabbit is 10 seconds.

To catch the rabbit, the dog needs to cover the

horizontal

distance of 46 meters and vertical distance of 28 meters.

Time taken by rabbit to cover 46 meters horizontally = Distance/Speed = 46/7.5 = 6.13 seconds (approx)

In this time, the rabbit would have covered a

vertical

distance of 10 x 6.13 = 61.3 meters.

So, the dog needs to cover a vertical distance of 28 - 61.3 = -33.3 meters (negative sign indicates that the dog needs to go downwards).

Time taken by dog to cover 33.3

meters

vertically = Distance/Speed = 33.3/5 = 6.66 seconds (approx)

Therefore, the total time taken by the dog to catch the rabbit = 6.13 + 6.66 = 10 seconds (approx)."

For such more question on

meters

https://brainly.com/question/30153116

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