Question

On a frictionless surface a block of mass M moving at speed V collides elastically with another block of same mass M which is initially at rest. After collision the first block moves at an angle q to its initial direction and has a speed $\frac{V}{3}$. The second block's speed after the collision is:
(a) $\frac{3}{4}V$
(b) $\frac{3}{\sqrt{2}}V$
(c) $\frac{\sqrt{3}}{2}V$
(d) $\frac{2\sqrt{2}}{3}V$

Answer 1

using conservation of kinetic energy as collision is elastic option d is right