Question

On a game show, a contestant randomly chooses a chip from a bag that contains numbers and strikes. The theoretical probability of choosing a strike is 1/5. The bag contains 8 strikes. How many chips are in the bag?

Answer 1

1/5 + x/8 =1

x + 8 = 5x

x = 2 chips

there are two chips in the bag

Answer 2

Therefore the number of chips in the bag is 32.

Step-by-step explanation:

Probability:

The ratio of the favorable outcomes to the total number of outcomes.

$Probability=\frac{\textrm{The favorable outcomes}}{\textrm{Total number of outcomes}}$

Given that,

The probability of choosing a strikes is $\frac15$. The bag contains 8 strikes.

Consider the number of chips in the bag be x.

Then total number of chips and  strikes is =(x+8)

The probability of choosing a strikes is

$=\frac{\textrm{Number of strikes}}{\textrm{Total number of strikes and chips}}$

$=\frac{8}{x+8}$

According to the problem,

$\frac{8}{x+8}=\frac15$

$\Rightarrow (x+8)=5\times 8$

$\Rightarrow x+8=40$

$\Rightarrow x=40-8$

$\Rightarrow x=32$

Therefore the number of chips in the bag is 32.