On a graph paper draw two straight lines which represent
x - 3y +1 + 0
and
2x = 3y = 4 = 0
. Also find the point of intersection of the two lines on the graph.
Answers
EXPLANATION.
Graph of straight lines.
⇒ x - 3y + 1 = 0. - - - - - (1).
⇒ 2x - 3y - 4 = 0. - - - - - (2).
As we know that,
From equation (1), we get.
⇒ x - 3y + 1 = 0. - - - - - (1).
Put the value of x = 0 in the equation, we get.
⇒ (0) - 3y + 1 = 0.
⇒ - 3y + 1 = 0.
⇒ - 3y = - 1.
⇒ 3y = 1.
⇒ y = 1/3.
⇒ y = 0.33.
Their Co-ordinates = (0,0.33).
Put the value of y = 0 in the equation, we get.
⇒ x - 3(0) + 1 = 0.
⇒ x + 1 = 0.
⇒ x = - 1.
Their Co-ordinates = (-1,0).
From equation (2), we get.
⇒ 2x - 3y - 4 = 0. - - - - - (2).
Put the value of x = 0 in the equation, we get.
⇒ 2(0) - 3y - 4 = 0.
⇒ - 3y - 4 = 0.
⇒ - 3y = 4.
⇒ y = - 4/3.
⇒ y = - 1.33.
Their Co-ordinates = (0,-1.33).
Put the value of y = 0 in the equation, we get.
⇒ 2x - 3(0) - 4 = 0.
⇒ 2x - 4 = 0.
⇒ 2x = 4.
⇒ x = 2.
Their Co-ordinates = (2,0).
Both curves intersects at a point = (5,2).
Answer:
☆1)x-3y+1=0.
Solve for y
y=1/3+x/3
Writing it in slope intercept form
y= 1 x + 1
3 3
Using slope intercept form we should find slope of y intercept.
Slope= 1
3
y- Intercept = 1
3
Any lines can be graphed using two points
x | y
0 | 2
2 | 1
Graph the line using the slope and the y -intercept.
☆2) 2x-3y-4=0
Put the value of x =0 in equation we get
=2 (0)-3y-4=0
-3y-4=0
-3y=4
y=-4/3
y=-1.33.
Their coordinates is =(0,-1.33)
☆Putting the value of y=0 in equation we get
2x-3 (0)-4=0
2x-4=0
2x=-4
x=-4/2
x=-2.
Their coordinates are (-2,0).
●☆Verification:
You can view the graph in given attachment.
And both the equation intersect at a point of (5,2)
Hope it helps u mate
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