Question

On a highway at a horizontal sharp turn of radius 20 m, a signboard indicate that the maximum speed of vehicles will be 20 m/s.
The minimum coefficient of friction between
tires of vehicle and road are
(a) 0.02
(b) 0.2
(c) 2
(d) 20

Answer 1

Answer:

c) 2 ....

Explanation:

WKT ......

V = √coefficient of friction × g× r

then , we have V = 20 m/ s , r = 20 m , and g = 9.8 m/s ....

then.....we use the formula ...

v*2 = coefficient of friction × g× r

400 = coefficient of friction × 9.8 × 20

400/ 9.8 × 20 = coefficient of friction

coefficient of friction = 400 / 196

coefficient of friction = 2.04

then coefficient of friction = 2 ......

...hence option c) is correct answer ....

hope you understand .....

Answer 2

Answer:

(c) 2 the right one answer