Question

on a hypothetical scale A the ice point is 42° and the steam point is 182° for another scale B. the ice point is -10° and steam point is 90° if B reads 60° the reading of A is​

Answer 1

Answer:

Bs - Bi = 90 - (-10) = 100   100 Db between ice and steam point

As - Ai = 182 - 42 = 140 Da between ice and steam point

100 Db = 140 Da        1 Db = 7/5 Da   relative magnitudes of degrees on scales of A and B

Nb = 60 - (-10)  = 70     B is 70 degrees above its ice point

Na = 70 * 7/5 = 98     A is 98 degrees above its point

Ta = 98 + 42 = 140     temperature of A when B is 60

More generally:

Ta = (Tb + 10) * 7/5 + 42

Tb = (Ta - 42) * 5/7 - 10

Then if Ta = 140   Tb = (140 - 42) * 5/7 - 10 = 60

and if Tb = 60   then Ta = (60 + 10) * 7/5 + 42 = 140

Answer 2

Ans

140°

Explanation

see the attachment