Question

On a hypothetical scale x the ice point is 40 and the steam point is 120. For another scale y the ice point and steam points are -30 and 130 respectively . If x reads 50. The reading of y is

Answer 1

Answer:

Y = -10

Explanation:

Let say  x scale  is   X =    LC + M

& y scale is  Y = PC + Q

L , M , P & Q  are constants    & C is value in deg Celsius

C = 0 (ice point )    &  C = 100 (Steam Point)

L*0 + M = 40 => M = 40

X = L*100 + M = 120 => 100L + 40 = 120 => 100L = 80 => L = 0.8

=> X = 0.8C + 40

P* 0 + Q = -30  =>  Q = -30

P*100 + Q = 130 => 100P -30 = 130  => 100P = 160 => P = 1.6

=> Y = 1.6C - 30

if X = 50

=> 50 = 0.8*C + 40

=> 0.8C = 10

=> C = 12.5

Y = 1.6 * 12.5 - 30

=> Y = 20 - 30

=> Y = -10

Answer 2

Answer:

-10

Explanation:

reading-l.f.p/u.f.p-l.f.p

x-40/120-40=y-(-30)/130-(-30)

x=50

50-40/120-40=y+30/130+30

10/80×180-30

10×2-30

20-30

-10