Question

On a level road , a Scooterist applies breaks to slow down from a speed of 10m/s to 5m/s . If the mass of Scooterist and the scooter be 150kg , Calculate the work done by the breaks .(Negative air resistance and friction).

STARS and Moderators help me out of this question.​

Answer 1

$\underline{\underline{\blue{\textbf{Step - By - Step - Explanation : -}}}}$

To Find :

• we need to find the work done by Scooterist.

Solution :

• mass = 150kg
• u = 10m/s
• v = 5m/s

Work done by break = Inetial k.E - Final K.E

W = 1/2mu² - 1/2mv²

w = 1/2 × m(u² - v²)

w = 1/2 × 150[(10)² - (5)²]

w = 75(100 - 25)

w = 75 × 75

w = 5625J

$\large\dag \large</p><p> { \red{\underline{\bf{Hence }}}}$

$\pink{\textrm{Work done by breaks = 5625 Joules}}$

━━━━━━━━━━━━━━━━━━━━━━━━━