Math, asked by prado2493, 1 year ago

On a line AB take four points P, Q, R and S in order such that PQ = RS state whether PR congruent to QS. Give reasons in support of your answer.

Answers

Answered by Karan2827
42

We are given

PQ=RS

we observe that QR is the common segment.

So by axiom "When equals are added to equals the sums are equal"

PQ+QR=RS=QR

PR=QS

Hence provED

Answered by amitnrw
16

PR congruent to QS if On a line AB take four points P, Q, R and S in order such that PQ = RS

Step-by-step explanation:

On a line AB take four points P, Q, R and S in order

=>

A   P   Q    R   S   B

PQ  = RS

A      P           Q            R              S       B    

        <----x-----><---y----><----x------>

Let say PQ = RS = x

& QR = y

PR  = PQ + QR

=> PR = x + y

QS = QR + RS

=> QS = y  + x

=> QS = x + y

=> QS = PR

=> PR = QS

Hence PR congruent to QS

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