Question

on a morning walk three person step out 30 cm 36 cm 40 cm respectively what is the minimum distance each should walk so that each can never the same distance in complete steps​

Answer 1

Solution:

Minimum distance  = LCM of 30,36,40

therefore ,

30 = 2×3×5

36 = 2×2×3×3

40 = 2×2×2×5

Thus the LCM of 30,36,40 = 360

Therefore the minimum distance each should walk = 3 m and 60 cm.

Answer 2

Answer:

The minimum Equal Distance they cover is 360 cm

Step-by-step explanation:

Given: Length of steps of 3 persons are 30 cm , 36 cm and 40 cm

To find: Minimum equal Distance they cover in complete steps.

Common Minimum value of numbers is The LCM (lowest common multiple) of those no.

So, To find minimum equal distance that they cover we find the LCM of 30 , 36 , 40.

We use factorization method to find LCM,

30 = 2 × 3 × 5

36 = 2 × 2 × 3 × 3

40 = 2 × 2 × 2 × 5

⇒ LCM = 2 × 3 × 5 × 2 × 2 × 3

            = 360

Therefore, The minimum Equal Distance they cover is 360 cm