Math, asked by meetramalvjprojam3a2, 1 year ago

On a morning walk,three persons step off together and their steps measure 40cm,42cm,45cm respectively.what is the minimum distance each should walk so that each can cover the same disance in complete steps?

Answers

Answered by Alisha260
1
LCM = Min. Distance 2 | 40, 42, 45 3| 20, 21 , 45 5| 20, 7 , 15 | 4, 7 , 3 LCM - 2x2x3x5x4x7x3 = 12 X 20 X 21 = 420x12 = 5040 (Ans) The minimum distance that they can walk in complete steps is 5040cm.

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Answered by nishu10122004
0

Answer:

Step-by-step explanation:

LCM(40,42,45)

first find LCM of 40

LCM(40)=2×2×2×5=2³×5

LCM(42)=2×3×7=2×3×7

LCM(45)=3×3×5=3²×5

LCM(40,42,45)=

2³×3²×7×5= 8×9×7×5=504×5= 2520

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