On a morning walk,three persons step off together and their steps measure 40cm,42cm,45cm respectively.what is the minimum distance each should walk so that each can cover the same disance in complete steps?
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LCM = Min. Distance
2 | 40, 42, 45
3| 20, 21 , 45
5| 20, 7 , 15
| 4, 7 , 3
LCM - 2x2x3x5x4x7x3 = 12 X 20 X 21 = 420x12 = 5040
(Ans) The minimum distance that they can walk in complete steps is 5040cm.
Alisha260:
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Answer:
Step-by-step explanation:
LCM(40,42,45)
first find LCM of 40
LCM(40)=2×2×2×5=2³×5
LCM(42)=2×3×7=2×3×7
LCM(45)=3×3×5=3²×5
LCM(40,42,45)=
2³×3²×7×5= 8×9×7×5=504×5= 2520
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