On a morning walk three persons step off together and their steps measure 40 cm, 42 cm and 45 cm respectively. What is the minimum distance each should walk so that each can cover the complete number of steps?
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the least distance will be the LCM of 40cm, 42cm and 45cm
which is 2520cm=25.2m
which is 2520cm=25.2m
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3
We have to find minimum distance, so we will take the LCM of 40, 42 and 45.
Prime factorisation :-
➡ 40 = 2×2×2×5 = 2³×5
➡ 42 = 2×3×7
➡ 45 = 3×3×5 = 3²×5
LCM ( 40, 42, 45 ) = 2³ × 3² × 5 × 7
= 2520
So, after 2520 cm or 2•520m they can cover the compete number of steps.
Hope it will help you !!
Prime factorisation :-
➡ 40 = 2×2×2×5 = 2³×5
➡ 42 = 2×3×7
➡ 45 = 3×3×5 = 3²×5
LCM ( 40, 42, 45 ) = 2³ × 3² × 5 × 7
= 2520
So, after 2520 cm or 2•520m they can cover the compete number of steps.
Hope it will help you !!
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