on a morning walk , three persons step off together and their steps measure 40cm, 42cm and 45cm respectively. whaat is the minimum distance each should walk so that each can cover the same distance in complete steps ?
those who will give the correct amswer, I will mark him/her as brainliest one.
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Answered by
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take LCM it it is 2520
susanna1:
okay thanks for ur answer
it really helped me
:)
We have to find the LCM of 40 cm, 42 cm and 45 cm to get the required minimum distance. Because we are asked the minimum distance
Now,
40 = 2 × 2 × 2 × 5,
42 = 2 × 3 × 7
45 = 3 × 3 × 5
∴ LCM (40, 42, 45) = 2 × 3 × 5 × 2 × 2 × 3 × 7 = 30 × 12 × 7 = 210 × 12 = 2520
Minimum distance each should walk 2520 cm. so that, each can cover the same distance in complete
Now,
40 = 2 × 2 × 2 × 5,
42 = 2 × 3 × 7
45 = 3 × 3 × 5
∴ LCM (40, 42, 45) = 2 × 3 × 5 × 2 × 2 × 3 × 7 = 30 × 12 × 7 = 210 × 12 = 2520
Minimum distance each should walk 2520 cm. so that, each can cover the same distance in complete
I hope this will help you
welcome
okay
thanks a lot
Answered by
2
We have to find the LCM of 40 cm, 42 cm and 45 cm to get the required minimum distance. Because we are asked the minimum distance
Now,
40 = 2 × 2 × 2 × 5,
42 = 2 × 3 × 7
45 = 3 × 3 × 5
∴ LCM (40, 42, 45) = 2 × 3 × 5 × 2 × 2 × 3 × 7 = 30 × 12 × 7 = 210 × 12 = 2520
Minimum distance each should walk 2520 cm. so that, each can cover the same distance in complete steps .
Plz mark it as braniliest .
Now,
40 = 2 × 2 × 2 × 5,
42 = 2 × 3 × 7
45 = 3 × 3 × 5
∴ LCM (40, 42, 45) = 2 × 3 × 5 × 2 × 2 × 3 × 7 = 30 × 12 × 7 = 210 × 12 = 2520
Minimum distance each should walk 2520 cm. so that, each can cover the same distance in complete steps .
Plz mark it as braniliest .
Plz mark it as braniliest if you like it
thanks for ur answer
it really helped me
:)
I will surely mark ur answer as brainliest
Thanks for marking me as braniliest
you are welcome
:-)
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