On a morning walk three persons step off together and their steps measure 40cm, 42cm and 45cm respectively. what is the minimum distance each should walk so that each can cover the same distance in complete steps?
Answers
Answered by
68
Hi,
In this case we have to find LCM of
three persons measure of steps
which indicates what is the minimum
distance each should walk so that
each can cover the same distance in
complete steps.
LCM of 40 cm , 42 cm , 45 cm,
5 l 40 , 42 , 45
_____________
2l 8 , 42 , 9
____________
2| 4 , 21 , 9
______________
3) 2 , 7 , 3
LCM = 5 × 2 × 2 × 3 × 4 × 7 × 3
= 2520
after 2520cm they can cover the same distance .
I hope this helps you.
:)
In this case we have to find LCM of
three persons measure of steps
which indicates what is the minimum
distance each should walk so that
each can cover the same distance in
complete steps.
LCM of 40 cm , 42 cm , 45 cm,
5 l 40 , 42 , 45
_____________
2l 8 , 42 , 9
____________
2| 4 , 21 , 9
______________
3) 2 , 7 , 3
LCM = 5 × 2 × 2 × 3 × 4 × 7 × 3
= 2520
after 2520cm they can cover the same distance .
I hope this helps you.
:)
Answered by
41
Answer:
We have to find the LCM of 40 cm, 42 cm and 45 cm
Steps measure 40 cm, 42 cm and 45 cm respectively.
Finding LCM individualy
⇒ 40 = 2 × 2 × 2 × 5
⇒ 42 = 2 × 3 × 7
⇒ 45 = 3 × 3 × 5
Total LCM
⇒ LCM (40, 42, 45) = 2 × 3 × 5 × 2 × 2 × 3 × 7
⇒ LCM (40, 42, 45) = 30 × 12 × 7
⇒ LCM (40, 42, 45) = 210 × 12
⇒ LCM (40, 42, 45) = 2520
Minimum distance of each person should walk is 2520 cm.
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