On a morning walk, three persons step out together and their steps
measure 30 cm, 36 cm and 40 cm respectively. What is the minimum
distance each should walk so that each can cover the same distance in
complete steps ?
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360cm is the minimum distance...
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sachin861:
3 ka square kese aaya
take the highest power of the no.
thus 3×3=3^2
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Answer:
The minimum equal distance they cover is 360 cm.
Step-by-step explanation:
Given: Length of steps of 3 persons are 30 cm, 36 cm, and 40 cm
To find: Minimum equal Distance they cover in complete steps.
The common Minimum value of numbers is The LCM (lowest common multiple) of those no.
So, To find the minimum equal distance that they cover we find the LCM of 30, 36, 40.
We use the factorization method to find LCM,
30 = 2 × 3 × 5
36 = 2 × 2 × 3 × 3
40 = 2 × 2 × 2 × 5
⇒ LCM = 2 × 3 × 5 × 2 × 2 × 3
= 360
Therefore, The minimum Equal Distance they cover is 360 cm.
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