on a morning walk three persons step out together and their steps measure 30cm ,36cm and 40cm respectively.what is the minimum distance each should walk so that each can cover the same distance in complete step?
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Answered by
5
given data...
consider 30, 36, 40 as numbers and split Their factors..
when u get their factors .....just find HCF...
u will get HCF as 2 ...that's Ua answer...i.e the distance covered..
consider 30, 36, 40 as numbers and split Their factors..
when u get their factors .....just find HCF...
u will get HCF as 2 ...that's Ua answer...i.e the distance covered..
Answered by
8
Answer:
The minimum distance each should walk is 360 cm.
Step-by-step explanation:
Here, the three person's steps measure 30 cm ,36 cm and 40 cm respectively.
Hence, the minimum distance each should walk so that each can cover the same distance in complete step. = L.C.M. of 30 ,36, 40
The factors of 30 = 2 × 3 × 5
The factors of 36 = 2 × 2 × 3 × 3
The factors of 40 = 2 × 2 × 2 × 5
L.C.M. (30, 36, 40) = 2 × 2 × 2 × 3 × 3 × 5 = 360
Thus, the minimum distance each should walk = 360 cm
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