Question

on a morning walk three persons steps together and their steps measure 40cm,42cm and 45 cm what is the maximum each should walk that each can cover the same distance in complete steps​

Answer 1

Step-by-step explanation:

SOLUTION:-

$Since \: the \: three \: persons \: start \\ walking \: together.  \: </p><p></p><p></p><p>$

$The \: minimum \: distance \: covered \:by \\each \: of \: them \: in \: complete \: steps$

$=LCM(40,42,45)$

$40=2×2×2×5= {2}^{3} ×5$

$42=2×3×7$

$45=3×3×5= {3}^{2} ×5$

$⇒LCM(40,42,45)= {2}^{3} × {3}^{2} ×5×7=2520$

$⇒ Each\: person \: should \: walk \: a \\ minimum \: distance \: of 2520 cm \\ in \: complete \: steps.$