On a motorway a car is moving with speed limit of 120km\h.by applying breaks the car comes to rest after covering a distance of 30m.what is deceleration of the car?
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Explanation:
u=120 km/h
=120 X 1000/3600
=100/3 m/s
use
v²=u²-2ah
0=(100/3)²-2×a×30
a=1000/27×2
a=81.51(approx.)
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