on a new scale of temperature (which is linear) and called " W" scale. the freezing and boiling points of water are 39degreeW and 239degreeW respectively what will be the temperature on the new scale, corresponding to a temperature of 39degree celcius on the celcius scale
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Given,T f
=39 0 WTb
=230 0 W
We know that,
100 0 C−0 0 CT b −T f
= 39 0 C
T−39 0 C
100239−39
= 39T−39
100200 = 39T−39
T−39=2×39=78 0 W
T=39+78=117 0 W
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