Question

on a new scale of temperature (which is linear) and called " W" scale. the freezing and boiling points of water are 39degreeW and 239degreeW respectively what will be the temperature on the new scale, corresponding to a temperature of 39degree celcius on the celcius scale​

Answer 1

ANSWER

Given,T f

=39 0 WTb

=230 0 W

We know that,

100 0 C−0 0 CT b −T f

= 39 0 C

T−39 0 C

100239−39

= 39T−39

100200 = 39T−39

T−39=2×39=78 0 W

T=39+78=117 0 W