on a number line coordinate of P Q R are 6, -10 and 12 respectively state true or false d( P,R) + d ( RQ) = ( PQ)
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Correct Question :-
On a number line coordinate of P -R- Q are 6, -10 and 12 respectively state true or false d(P,R) + d (R,Q) = d(P,Q).
Answer :-
False [d(P,R) + d(R,Q) ≠ d(P,Q)]
Given :-
- PQ = 6
- QR = -10
- PR = 12
To Find :-
- State true or false : d(P,R) + d(R,Q) = d(P,Q).
Solution :-
We have, PQ = 6, QR = -10, PR = 12.
According to Question :-
Case (I) :-
↪d(P,R) + d(R,Q) = 12 + (-10)
↪d(P,R) + d(R,Q) = 12 - 10
↪d(P,R) + d(R,Q) = 2 __________eqn.(1)
Case (II) :-
↪d(P,Q) = 6 ________________eqn. (2)
From eqn.(1)&(2) :-
d(P,R) + d(R,Q) ≠ d(P,Q)
.°. P - R - Q is not collinear.
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