On a number line points A,B and C are collinear points such. that d ( A, C) =15,d(C,B)=5.find d(A,B) considering all possibilities?
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Answer:
The distance of the point (A, C) is 15 and distance of the points (C, B) is 5.
As the 3 points are collinear than distance of (A, C) = sum of distances of (C, B) and (A, B)
or 15 =5 +d(A,B)
or d(A,B) = 15-5=0
Hence distance of the point (A, B) is 10
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